Answer:
47,070 J are needed to increase the temperature of 150 g of water from 25 degrees C to its boiling point of 100 degrees C.
Step-by-step explanation:
25 degrees Celsius is 298 degrees Kelvin; 100 degrees Celsius, 373 degrees Kelvin. = 150 g x 4.184 J/g/K x (373 - 298) K = 47,070 J. Thus, 47,070 J are needed to increase the temperature of 150 g of water from 25 degrees C to its boiling point of 100 degrees C.