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Prove that 1/sec0-tan0= sec0+tan0
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Prove that 1/sec0-tan0= sec0+tan0

User Karthik Rk
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Answer:

Explanation:


\text{LHS}=(1)/(\sec \theta-\tan \theta)\\=(\sec \theta+\tan \theta)/((\sec \theta-\tan \theta)(\sec \theta+\tan \theta))\\=(\sec \theta+\tan \theta)/(\sec^(2) \theta-\tan^(2) \theta)\\=(\sec \theta+\tan \theta)/(1)\\=\sec \theta+\tan \theta\\=\text{RHS}

User Joseph Leedy
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