Question

Prove that 1/sec0-tan0= sec0+tan0

Answer 1

Explanation:

`\text{LHS}=(1)/(\sec \theta-\tan \theta)\\=(\sec \theta+\tan \theta)/((\sec \theta-\tan \theta)(\sec \theta+\tan \theta))\\=(\sec \theta+\tan \theta)/(\sec^(2) \theta-\tan^(2) \theta)\\=(\sec \theta+\tan \theta)/(1)\\=\sec \theta+\tan \theta\\=\text{RHS}`