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If it is known that function f is odd and function g is even. determine if the following

functions are odd, even, or neither odd nor even.
1/g(x)

2 Answers

10 votes

Final answer:

The function 1/g(x) is even.

Step-by-step explanation:

Given that function f is odd and function g is even, we want to determine the nature of the function 1/g(x).

An odd function has the property: f(-x) = -f(x), while an even function has the property: g(-x) = g(x).

Using these properties, let's analyze 1/g(x):

  1. When we substitute -x in 1/g(x), we get 1/g(-x).
  2. Since g(x) is even, g(-x) = g(x), so 1/g(-x) becomes 1/g(x).
  3. The fact that 1/g(x) = 1/g(-x) means that the function is even.

Therefore, the function 1/g(x) is even.

User Jeron
by
8.4k points
3 votes

Answer:


(1)/(g)\ \text{ is an even function}

Step-by-step explanation:

Considers the function h defined by :

h(x) = 1/g(x)

g is an even function means g(-x) = g(x)

then

h(-x) = 1/g(-x) = 1/g(x) = h(x)

Therefore

h is an even function.

User Gareth Stockwell
by
8.2k points

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