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LCM of a2+b2 and a4-b4​

User Dbush
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1 Answer

3 votes

Answer:

The LCM is:


(a^2+b^2)(a+b)(a-b)

Explanation:

Given polynomials are:


a^2+b^2\\a^4 - b^4

We can use factorization to find the LCM of the given polynomials.

Taking the second polynomial, using the identity


a^2 - b^2 = (a+b)(a-b)

Applying on 2nd polynomial


(a^2)^2-(b^2)^2\\=(a^2+b^2)(a^2-b^2)\\=(a^2+b^2)(a+b)(a-b)

We can see that
a^2+b^2 is common in both polynomials, it will be counted only one time. The LCM of given polynomials is:


(a^2+b^2)(a+b)(a-b)

User Josh Valdivieso
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