Answer:
v₂ = 22.13 m/s
We need to measure heights of both points and the law of conservation of energy is applied to measure this speed.
Step-by-step explanation:
In order to find the speed at the point B, we will use the Law of conservation of energy between points A and B to get the required results, as follows:
Total Energy of Cart at Point A = Total Energy of Cart Point B
K.E at A + P.E at A = K.E at B + P.E at B
(1/2)mv₁² + mgh₁ = (1/2)mv₂² + mgh²
(1/2)m(v₁² - v₂²) = mg(h₂ - h₁)
(1/2)(v₁² - v₂²) = g(h₂ - h₁)
where,
v₁ = velocity of cart at Point A = 0 m/s
v₂ = Velocity of Cart at Point B = ?
h₁ = height of point A relative to the ground = 35 m
h₂ = height of point B relative to the ground = 10 m
g = 9.8 m/s²
Therefore,
(1/2)[(0 m/s)² - v₂²] = (9.8 m/s²)(10 m - 35m)
- v₂² = - (2)(245 m²/s²)
v₂ = √(490 m²/s²)
v₂ = 22.13 m/s
We need to measure heights of both points and the law of conservation of energy is applied to measure this speed.