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Question:Fibonacci

1. Here are the first 5 terms of a quadratic sequence.
1
3
7
13
21
Find an expression, in terms of n for the nth term of this quadratic sequence.

User KumarM
by
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1 Answer

6 votes

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Answer:

n² -n +1

Explanation:

First differences of the terms of the sequence are ...

3-1 = 2

7-3 = 4

13-7 = 6

21-13 = 8

Second differences are ...

4-2 = 2

6-4 = 2

8-6 = 2

In a quadratic sequence the coefficient of the squared term is half of the second difference value. Here, that means the squared term will be (2/2)n² = n².

__

We can find the other terms of the quadratic expression by considering the differences between n² and the actual sequence.

The sequence of n² terms is ...

1, 4, 9, 16, 25

When we subtract these from the actual sequence, we get ...

1-1 = 0

3-4 = -1

7-9 = -2

13-16 = -3

21-25 = -4

That is, the amount subtracted from n² is one less than the term number.

The expression for the n-th term is ...

an = n² -n +1

User Juan Serrats
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