Answer:
I was riding in the wagon when it had the greatest acceleration during start up.
According to Newton's Second Law of Motion,
Force, F = [m = mass of the object, v = velocity of the object]
F = m + v
As the m is constant here, so the equation will be,
F = m
or, F = m×a , a is the acceleration
Between Tom and I,
Now, if the Force applied is same,
a ∝ 1/m
As Tom is bigger than me, so in the first case, I was riding in the wagon when it had the greatest acceleration during start up.
In the second case,
The force is not same.
Sara applies more force than both of us and she is the exact same size as me.
If m is same, then,
F ∝ a
So, in the second case, Sara is in the wagon when it has the greatest acceleration.
Step-by-step explanation:
1. As both me and Tim have the same amount of force and are able to pull the same weight with the same effect. However, Tim’s weight is greater than mine, so when I pull him it’s harder at the start as he is bigger and heavier than me. If I was to be 35 kg and he was about ⅓ more my weight.
My power=Tims power
My weight<Tims weight This creates a gap
So in conclusion , Tims speed at the start would be greater than mine asI weight less than him.
2. My power<Sara’s power
My weight=Sara’s weight This creates a gap
This end up that Saras acceleration is greater than mine as she is even stronger than me.