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What is the rotational inertia in units of kgm2 of a long thin rod of mass 1.0 kg and length 0.6 m if it rotates about one of its ends?

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Answer:


I=0.12\ kg-m^2

Step-by-step explanation:

Given that,

Mass of a thin rod, m = 1 kg

Length of the rod, l = 0.6 m

We need to find the rotational inertia of the rod if it rotates about one of its ends. It can be given by the formula as follows :


I=(1)/(3)ML^2\\\\I=(1)/(3)* 1* (0.6)^2\\\\=0.12\ kg-m^2

So, the moment of inertia of the rod about one of its ends is
0.12\ kg-m^2.

User Yamen Ajjour
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