Answer:
![I=0.12\ kg-m^2](https://img.qammunity.org/2021/formulas/physics/college/2e7jw8hoydoolg0p326uj9xpx7qzf5fq61.png)
Step-by-step explanation:
Given that,
Mass of a thin rod, m = 1 kg
Length of the rod, l = 0.6 m
We need to find the rotational inertia of the rod if it rotates about one of its ends. It can be given by the formula as follows :
![I=(1)/(3)ML^2\\\\I=(1)/(3)* 1* (0.6)^2\\\\=0.12\ kg-m^2](https://img.qammunity.org/2021/formulas/physics/college/8boh2g1zbe73kswhkxvd60am0x2d4nv6xk.png)
So, the moment of inertia of the rod about one of its ends is
.