Question

A red blood cell contains 4.8 107 free electrons. What is the total charge of these electrons in the red blood cell?

Answer 1

Charge,
`q=7.68* 10^(-12)\ C`

Step-by-step explanation:

It is given that,

The number of electron in a RBCs,
`n=4.8* 10^7`

We need to find the total charge of these electrons in the red blood cell. Let it is q. Using the quantization of charge as follows :

q = ne

e is the change on electron

`q=4.8* 10^7* 1.6* 10^(-19)\\\\q=7.68* 10^(-12)\ C`

So, the net charge is
`7.68* 10^(-12)\ C`.