Answer:
(a) 1,902,231,808,400
(b) 84
(c) 20
Explanation:
In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.
The formula to compute the combinations of k items from n is given by the formula:
![{n\choose k}=(n!)/(k!\cdot(n-k)!)](https://img.qammunity.org/2021/formulas/mathematics/college/kjoqt8bwu8pz8llf1bdim58to0uvicqap1.png)
(a)
Compute the number of ways to select 9 applicants from 100 as follows:
![{100\choose 9}=(100!)/(9!\cdot(100-9)!)](https://img.qammunity.org/2021/formulas/mathematics/college/9qu0cg4qbszdnrfeve48y1tbkxxsqen8ze.png)
![=(100!)/(9!* 91!)\\\\=(100* 99* 98* 97* 96* 95* 94* 93* 92* 91!)/(9!* 91!)\\\\=(100* 99* 98* 97* 96* 95* 94* 93* 92)/(9!)\\\\=1902231808400](https://img.qammunity.org/2021/formulas/mathematics/college/51sqy0x3mca06ewu070sljmnk8jyeaj0id.png)
(b)
Compute the number of ways to select 6 people from 9 as follows:
![{9\choose 6}=(9!)/(6!\cdot(9-6)!)](https://img.qammunity.org/2021/formulas/mathematics/college/c45rjd9sn4t8i56hjwo86qmuuzcxup9zog.png)
![=(9!)/(6!* 3!)\\\\=(9* 8* 7* 6!)/(6!* 3!)\\\\=(9* 8* 7)/(3!)\\\\=84](https://img.qammunity.org/2021/formulas/mathematics/college/l3gynr6atn8pwwztslueilerc9kyv8wc0d.png)
(c)
Compute the number of ways to select top 3 candidates from 6 as follows:
![{6\choose 3}=(6!)/(3!\cdot(6-3)!)](https://img.qammunity.org/2021/formulas/mathematics/college/6gbg8wwhb2uu6lgfm6aiunm85314mtuekt.png)
![=(6!)/(3!* 3!)\\\\=(6* 5* 4* 3!)/(3!* 3!)\\\\=(6* 5* 4)/(3!)\\\\=20](https://img.qammunity.org/2021/formulas/mathematics/college/db040hwbfi0t6uovlvx5rsqxhe1j10pcjx.png)