Answer:
The ball will go as high as 8.46 m
Step-by-step explanation:
Projectile Motion
It's the type of motion that experiences an object launched at a certain height above the ground and moves along a curved path exclusively under the action of gravity.
Being vo the initial speed of the object, θ the initial launch angle, and g the acceleration of gravity, then the maximum height hm can be calculated as follows:
![\displaystyle h_m=(v_o^2\cdot \sin^2\theta)/(2g)](https://img.qammunity.org/2021/formulas/physics/college/hq7ha6j11ins9m6ecsz9x46sx6str3s170.png)
The soccer ball is kicked at a speed of vo=24 m/s at an angle of θ=31°. Taking the value of
, then:
![\displaystyle h_m=(24^2\cdot \sin^2 31^\circ)/(2\cdot 9.8)](https://img.qammunity.org/2021/formulas/physics/college/feiltd6mc586rjx42nh4triylc600sulr6.png)
![\displaystyle h_m=(576\cdot 0.2653)/(19.6)](https://img.qammunity.org/2021/formulas/physics/college/2nm3h9r34t7faz1gee2aflywhzr4e568ik.png)
![h_m=7.80~m](https://img.qammunity.org/2021/formulas/physics/college/m3v6zymv0918158c4wglt6i096ldcayat8.png)
The ball will go as high as 8.46 m