Final answer:
There are approximately 8.2 oxygen atoms in Ca(H2PO4)2.
Step-by-step explanation:
The fertilizer Ca(H2PO4)2 contains calcium (Ca), hydrogen (H), phosphorus (P), and oxygen (O). To determine the number of oxygen atoms in the fertilizer, we need to calculate the number of moles of Ca(H2PO4)2 and then use the balanced chemical equation to find the ratio between oxygen atoms and moles of Ca(H2PO4)2.
The balanced chemical equation shows that for every 5 moles of Ca(H2PO4)2, there are 41 oxygen atoms. So, we can set up a proportion to find the number of oxygen atoms:
5 moles Ca(H2PO4)2 = 41 oxygen atoms
x moles Ca(H2PO4)2 = y oxygen atoms
Solving for y, we find that there are approximately 8.2 oxygen atoms in Ca(H2PO4)2.