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Suppose a box contains 3 defective light bulbs and 9 good bulbs. Three bulbs are chosen from the box without

replacement. What is the probability that at least one of the bulbs drawn is defective?

User Chelmertz
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1 Answer

7 votes

Answer:

1/4

Explanation:

3+9=12

12/3=4

User Iuridiniz
by
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