Register
Suppose a box contains 3 defective light bulbs and 9 good bulbs. Three bulbs are chosen from the box without replacement. What is the probability that at least one of the bulbs drawn is defective?
163k views
2 votes
Suppose a box contains 3 defective light bulbs and 9 good bulbs. Three bulbs are chosen from the box without

replacement. What is the probability that at least one of the bulbs drawn is defective?

User Chelmertz
by
6.1k points

1 Answer

7 votes

Answer:

1/4

Explanation:

3+9=12

12/3=4

User Iuridiniz
by
6.5k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

6.6m questions

8.7m answers

Other Questions

What is the least common denominator of the four fractions 20 7/10 20 3/4 18 9/10 20 18/25
What is 0.12 expressed as a fraction in simplest form
Solve using square root or factoring method plz help!!!!.....must click on pic to see the whole problem
What is the initial value and what does it represent? $4, the cost per item $4, the cost of the catalog $6, the cost per item $6, the cost of the catalog?
What is distributive property ?
Link Copied!