Determine the specific heat of a metal that has a mass of 34.57 g that absorbs 678 J of heat and is heated from 25.0 °C to 55.0 °C.

asked Nov 24, 2023 136k views

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4 votes

Answer:
$0.654 \text{ J/g} \cdot ^(\circ)\text{C}}$

Step-by-step explanation:

$678=(34.57)(c)(55.0-25.0)\\\\c=(678)/(34.57(55.0-25.0)) \approx \boxed{0.654 \text{ J/g} \cdot ^(\circ)\text{C}}}$

Dong Ma answered Nov 28, 2023

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