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The particle of 2 velocities 10m/s due east and 12m/S in the direction 30N/E. What is the resultant velocity and the direction?
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The particle of 2 velocities 10m/s due east and 12m/S in the direction 30N/E. What is the resultant velocity and the direction?

User Mossaddeque Mahmood
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1 Answer

7 votes

Step-by-step explanation:

My other answer got deleted for some unknown reason, so I will be breif:

Add the vertical components of the two forces and the horizontal components of the two forces.....use these to find the mag and direction

Vertical = 0 + 12 sin 30 = 6 m/s

Horizontal = 10 + 12 cos 30 = 20.39 m/ s

mag = sqrt ( 6^2 + 12.39^2) = 21.26 m/s

Direction = arctan ( 6/20.39) = 16.4 degrees N of E

User Dimbo
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