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THIS IS MY TEST IN GEOMETRY HELP

What is the angle of depression from the start of a 6-foot high access ramp that ends at a point 40 feet away along the ground? Nearest tenth of a degree.

User Ohioma
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Given:

Height of access ramp = 6 foot

Ramp ends at a point 40 feet away along the ground.

To find:

The angle of depression in nearest tenth of a degree.

Solution:

Using the given information, draw a figure as shown below.

In a right angle triangle,


\tan \theta = \frac{\text{Perpendicular}}{\text{Base}}

In triangle ABC,


\tan \theta=(AB)/(BC)


\tan \theta=(6)/(40)


\tan \theta=0.15

Taking tan inverse on both sides.


\theta=\tan^(-1)(0.15)


\theta=8.5307656


\theta \approx 8.5

Therefore, the angle of depression is 8.5 degrees.

THIS IS MY TEST IN GEOMETRY HELP What is the angle of depression from the start of-example-1
User Wolfcastle
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