Question

If 8.793 of heat are added to a 2.00g sample of metal and the temperature increases by 4.9°C. What is the specific heat?

Answer 1

The specific heat of metal = 0.897 J/g° C

Further explanation

Heat absorbed can be calculated using the formula:

Q = mc∆T

Q = heat, J

m = mass, g

c = specific heat, joules / g ° C

∆T = temperature difference, ° C / K

Q = 8.793 J

m = 2 g

∆t = 4.9 °C

`\tt c=(Q)/(m.\Delta t)\\\\c=(8.793)/(2* 4.9)\\\\c=0.897~J/g^oC`