Answer:
56500J
Step-by-step explanation:
Given parameters:
Mass of water = 25g = 0.025kg
Temperature of the water = 100°C
Unknown:
Amount of heat required to vaporize the water = ?
Solution:
The amount of heat required to vaporize the water is a function of the mass of the water and the latent heat of vaporization of water.
H = mL
H is the amount of heat
m is the mass
L is the latent heat of vaporization of water = 22.6 x 10⁵J/Kg
H = 0.025 x 22.6 x 10⁵ = 56500J