Answer:
The average acceleration of the cyclist is 5 m/s²
Step-by-step explanation:
Given;
initial velocity of the cyclist, u = 10 m/s
final velocity of the cyclist, v = 20 m/s
initial time of the cyclist, t₁ = 4 seconds
final time of the cyclist, t₂ = 6 seconds
The average acceleration is given by;
![a = (dv)/(dt)\\\\a = (v-u)/(t_2-t_1)\\\\a = (20-10)/(6-4)\\\\a = 5 \ m/s^2](https://img.qammunity.org/2021/formulas/physics/high-school/t1j6malytihns73sl8ri2una1o2lzwu2l1.png)
Therefore, the average acceleration of the cyclist is 5 m/s²