Question

How do I write log7t as a base 2 logarithm?

Answer 1

Given:

The value is
`\log_7t`.

To find:

The value as a base 2 logarithm.

Solution:

We know that,

`\log_xy=(\log_ay)/(\log_ax)`

where, a is any positive value.

We have,

`\log_7t`

Using the above property of logarithm, we get

`\log_7t=(\log_at)/(\log_a7)`

For a=2,

`\log_7t=(\log_2t)/(\log_27)`

Therefore, the given value as a base 2 logarithm can be written as
`(\log_2t)/(\log_27)`.