How do I write log7t as a base 2 logarithm?

Question

asked Jun 8, 2021 7.9k views

1 Answer

Sambhaji · Answer 1 · 2021-06-14T06:20:02+0000

Given:

The value is
$\log_7t$ .

To find:

The value as a base 2 logarithm.

Solution:

We know that,

$\log_xy=(\log_ay)/(\log_ax)$

where, a is any positive value.

We have,

$\log_7t$

Using the above property of logarithm, we get

$\log_7t=(\log_at)/(\log_a7)$

For a=2,

$\log_7t=(\log_2t)/(\log_27)$

Therefore, the given value as a base 2 logarithm can be written as
$(\log_2t)/(\log_27)$ .