Question

Solve each system of equations algebraically x-y=6 y=-1

Answer 1

x-(-1)=6

-x=6

-x/-1 6/-1

x=-6

Answer 2

Therefore, the solution of the system of equations will be:

`x=5,\:y=-1`

Explanation:

Given the system of equations

`x-y=6;\:y=-1`

solving

`\begin{bmatrix}x-y=6\\ y=-1\end{bmatrix}`

`\mathrm{Subsititute\:}y=-1`

`\begin{bmatrix}x-\left(-1\right)=6\end{bmatrix}`

`\begin{bmatrix}x+1=6\end{bmatrix}`

Isolate x for
`x+1=6`

`x+1=6`

`x=5`

Therefore, the solution of the system of equations will be:

`x=5,\:y=-1`