Question

A student wants to launch a tennis ball horizontally just over a 6.0 m high fence and have it land at approximately 20.0 m beyond the fence. What speed would the tennis ball need to have to land at this approximate distance?

Answer 1

Step-by-step explanation:

Time taken for vertical displacement will be equal to time taken for horizontal displacement .

Let it be t

for vertical fall , initial velocity u = 0

h = ut + 1/2 gt²

6 = 0 + .5 x 9.8 t²

t = 1.1065 s

horizontal displacement = horizontal velocity x time

20 = horizontal velocity x 1.1065

horizontal velocity = 18 m /s approx.