Question

What is the horizontal component of a ball thrown at a 27 degree angle at 16 m/s?

Answer 1

14.25 m/s

Step-by-step explanation:

In this problem, we need to find the horizontal component of a ball thrown at a 27 degree angle at 16 m/s.

It can be given by :

`v_x=v\cos\theta\\\\=16* \cos(27)\\\\=14.25\ m/s`

So, the horizontal component of the ball is 14.25 m/s.