Question

A line passes through the points (-3, 14) and (-1, 16). What is its equation in slope-intercept form?​

Answer 1

y = 6x + 22

General Formulas and Concepts:

Pre-Alg

• Order of Operations: BPEMDAS

Algebra I

Slope Formula:
`m=(y_2-y_1)/(x_2-x_1)`

Slope-Intercept Form: y = mx + b

• m - slope

• b - y-intercept

Explanation:

Step 1: Define

Point (-3, 14)

Point (-1, 16)

Step 2: Find slope m

1. Substitute:
   `m=(16-14)/(-1+3)`
2. Subtract/Add:
   `m=(12)/(2)`
3. Divide:
   `m=6`

Step 3: Find y-intercept b

1. Define: y = 6x + b
2. Substitute: 16 = 6(-1) + b
3. Multiply: 16 = -6 + b
4. Isolate b: 22 = b
5. Rewrite: b = 22

Step 4: Write linear equation

y = 6x + 22