HURRY! One of the roots of the equation 5x^(2) -12x+c=0 is 5 times as big as the other root. Find the value of c. NOT C=5.4

Question

HURRY! One of the roots of the equation
`5x^(2) -12x+c=0` is 5 times as big as the other root. Find the value of c.

NOT C=5.4

Answer 1

c = 4

Explanation:

x + 5x = 12/5

30x = 12

`x_(1)` = 2/5

`x_(2)` = 2

c = [(2/5)*2] * 5 = 4

(5x - 2)(x - 2) = 0

5x² - 12x + 4 = 0