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Eliminate the parameter:
x = 2cost-1 y = 3sint+ 4

User Bao
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1 Answer

9 votes

Answer:

Hi,

Explanation:


\left\{\begin {array} {ccc}x&=&2*cos(t)-1\\y&=&3*sin(t)+4\\\end{array}\right.\\\\\\\left\{\begin {array} {ccc}(x+1)/(2)&=&cos(t\\(y-4)/(3)&=&sin(t)\\\end{array}\right.\\\\Squaring\\\\\boxed{((x+1)/(2))^2+((y-4)/(3))^2&=1}\\

The curve is an ellipse having (-1,4) as center and half-axis (2 and 6)

User Kanani
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