Answer:
the answer is 0
Explanation:
r = -38
For what value of r in the formula: f(x) = 2x4 + x3 + x2- 3x + r does f(2) = 0?
Replace x with 2: 2·24 + 23 + 22- 3·2 + r = 32 + 8 + 4 - 6 + r = 38 + r
This value is to equal 0: 38 + r = 0
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