Question

If Sin A = 3÷5 and Cos B =6÷10, where A and B are acute angles determine
Sin(A-B)​

Answer 1

Explanation:

`\sin( \alpha - \beta ) = \sin( \alpha ) \cos( \beta ) - \cos( \alpha ) \sin( \beta )`

Using the Pythagorean theorem,

`\cos( \alpha ) = (4)/(5)`

`\sin( \beta ) = (8)/(10)`

`\sin( \alpha - \beta ) = ( (3)/(5) )( (3)/(5) ) - ( (4)/(5) )( (4)/(5) )`

`(9)/(25) - (16)/(25) = ( - 7)/(25)`