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A 6 foot shadow is cast by a 10 foot lamp post. What is the angle of elevation of the sun?

User BAERUS
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2 Answers

10 votes

Let that be theta

  • tanØ=Perpendicular/Base

Here perpendicular is lamp post and base is the shadow

  • tanØ=10/6
  • tanØ=5/3
  • tanØ=1.67
  • Ø=59°
User Nick Kavadias
by
4.7k points
9 votes

Answer:

59.0° (nearest tenth)

Explanation:

This can be modeled as a right triangle (see attachment).

To find the angle of elevation (marked as
x on the attached diagram), use the tan trig ratio:

Tan trigonometric ratio


\sf\tan(\theta)=(O)/(A)

where:


  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle

Given:


  • \theta = x
  • O = 10
  • A = 6

Substitute the given values into the formula and solve for x:


\implies \sf\tan(\theta)=(10)/(6)


\implies \sf\theta=\tan^(-1)\left((10)/(6)\right)


\implies \theta = \sf 59.03624...^(\circ)


\implies \theta = \sf 59.0^(\circ)\:(nearest\:tenth)

A 6 foot shadow is cast by a 10 foot lamp post. What is the angle of elevation of-example-1
User Geny
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4.8k points