Question

A tiger leaps horizontally from a 6.2 m high rock with a speed of 3.4 m/s. How far from the base of the rock will she land?

Answer 1

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Answer 2

First you will have to find how long Tiger stays in the air...since we consider the horizontal motion to be constant, then we have to find it using vertical motion...
y = vot + 1/2at*2
Tiger's vertical motion is 0 to begin with...
6.3 m = 0 + 1/2(9.8 m/s*2)t*2
t = 1.13 s
Second, how far horizontally will Tiger travel in that time...
v = d/t or d = vt = 3.5 m/s(1.13 s) = 4.0 m