If 8. 0 ml of water is added to 2. 0 ml of a 0. 500 m koh solution, the concentration of koh is changed to.

Charleetm asked Jan 18, 2023

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Charleetm asked Jan 18, 2023

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11 votes

Answer: 0.1 M

Step-by-step explanation:

Originally,
$0.500=\frac{\text{moles of solute}}{0.002}$ , so there was 0.001 mol of KOH.

Now, there is 8.0+2.0=10.0 mL of solution, so the new concentration is:

$(0.001)/(0.01)=\boxed{0.1 \text{ M}}$

Chuim answered Jan 23, 2023

by Chuim

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