Answer:
4092
Explanation:
r = 2
a1 = 4×(2)^(1 - 1) = 4
S10 = a1×((1 - r^10)/(1 - r)
= 4×((1 - 2^10)/(1 - 2))
= 4×((1 - 2^10)/-1)
= 4×(-(1 - 2^10))
= -4×(1 - 2^10)
= -4 + 4 × 2^10
= -4 + 2^2 × 2^10
= -4 + 2^12
= -4 + 4096
= 4092
Given is a GP with:
We need to find the sum of the first 10 terms:
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