229k views
1 vote
Write the linear equation in Slope-Intercept Form y = mx + b of the line that passes through the given points, then graph

the line.

Write the linear equation in Slope-Intercept Form y = mx + b of the line that passes-example-1

2 Answers

5 votes

Answer:

y = 3x + 7.

To graph the line mark off the 2 points and draw a line through them.

Explanation:

The slope = (-2-7) / (-3-0)

= -9/-3

= 3.

The value of b is found using the point-slope form of a line:

y - y1 = m(x - x1)

using m = 3, (x1, y1) = (0, 7):

y - 7 = 3(x - 0)

y = 3x + 7.

User YXD
by
8.5k points
4 votes

The equation in Slope-Intercept Form is y = 3x + 7.

The linear equation in Slope-Intercept Form, y = mx + b, of the line that passes through the points (0, 7) and (-3, -2), along with its graph:

1. Finding the slope (m):

m = (y2 - y1) / (x2 - x1)

m = (-2 - 7) / (-3 - 0)

m = -9 / -3

m = 3

2. Finding the y-intercept (b):

We can use either of the given points to plug into the equation y = mx + b to solve for b. Let's use the point (0, 7):

7 = 3(0) + b

7 = 0 + b

b = 7

3. Writing the equation in Slope-Intercept Form:

y = mx + b

y = 3x + 7

Write the linear equation in Slope-Intercept Form y = mx + b of the line that passes-example-1
User Ian Bytchek
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories