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What is the solution for x2 + 4x < 77? –11 < x < 7 –7 < x < 11 x < –7 or x > 11 x < –11 or x > 7

2 Answers

2 votes

Answer:

x < –11 or x > 7 is the correct answer!!

Explanation:

The answer above this was just slightly wrong. I took the exam and put my answer as option b and got it correct. Here is how I solved it correctly!

To solve the inequality x^2 + 4x > 77, we can factor the quadratic expression as (x - 7)(x + 11) > 0

To determine the solution, we consider the signs of each factor:

(x - 7) > 0 and (x + 11) > 0

This means x is greater than 7 or x is less than -11.

So, the simplified solution to the inequality x^2 + 4x > 77 is:

x < -11 or x > 7

User Abnab
by
4.2k points
7 votes

Answer:

-11 < x < 7

Explanation:

Inequalities:

x² + 4x < 77

Subtract 77 from both sides

x² + 4x - 77 < 0

To find the zero points (Roots),

Make x² + 4x - 77 = 0

Now find the factors

x² + 11x - 7x - 77 = 0

x(x + 11) - 7(x + 11) = 0

(x +11) (x - 7) = 0

x + 11 = 0 or (x -7) = 0

x = -11 or x = 7

So, the solutions of the inequality is between (-11) and 7

-11 < x < 7

User Serhii Londar
by
4.7k points