Answer:
The required equation of line in point-slope form is:
![y-6 = -7(x-3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/svyye88kb9zvcn7no5vjueuzpam9pt26go.png)
Explanation:
Given points are:
(x1,y1) = (3,6)
(x2,y2) = (5,-8)
The point-slope form of an equation is given by:
![y-y_1 = m(x-x_1)](https://img.qammunity.org/2021/formulas/mathematics/high-school/gpd6dxqzw1r1dhvzr31w0nsltz143w0zsb.png)
Here m is slope of the line and (x1,y1) is a point on line
The slope is calculated using the formula:
![m = (y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2021/formulas/mathematics/high-school/qpav2tpezfjoebw1smt5zxyas28f0tlb4m.png)
Putting the values we get
![m = (-8-6)/(5-3)\\m=(-14)/(2)\\m= -7](https://img.qammunity.org/2021/formulas/mathematics/high-school/3ketnsai0xmu5718x2b1ay0v0142d8yote.png)
Putting in the equation
![y-y_1 = -7(x-x_1)](https://img.qammunity.org/2021/formulas/mathematics/high-school/apshtqmouttoi3ntzw965r6iary2ec7act.png)
Now we have to put a point in the equation, putting (3,6) in the equation
![y-6 = -7(x-3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/svyye88kb9zvcn7no5vjueuzpam9pt26go.png)
Hence,
The required equation of line in point-slope form is:
![y-6 = -7(x-3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/svyye88kb9zvcn7no5vjueuzpam9pt26go.png)