Question

HELP ME PLEASEEEE!!

High School is selling Valentine's Day gifts as a fundraising event. One long stemmed rose costs $3.00 while one long stemmed carnation costs $1.50. If 50 orders were placed and they totaled $195, how many roses and carnations were ordered?

Answer 1

To find the number of roses and carnations ordered, we can set up a system of equations with the information given. By solving the system, we find that 80 roses were ordered, but no carnations.

Step-by-step explanation:

To solve this problem, let's assume the number of roses ordered is represented by the variable 'r' and the number of carnations ordered is represented by the variable 'c'.

According to the information given, one long stemmed rose costs $3.00 and one long stemmed carnation costs $1.50. We can set up the following equations:

1. 3r + 1.5c = 195 (equation 1)
2. r + c = 50 (equation 2)

Now we can solve this system of equations. We can multiply equation 2 by 1.5 to make the coefficients of 'r' in both equations equal:

1. 1.5r + 1.5c = 75 (equation 3)

By subtracting equation 3 from equation 1, we can eliminate 'c' and solve for 'r':

1. (3r + 1.5c) - (1.5r + 1.5c) = 195 - 75
2. 1.5r = 120
3. r = 80

So, 80 roses were ordered. To find the number of carnations, we can substitute the value of 'r' into equation 2:

1. 80 + c = 50
2. c = -30

Since the number of carnations cannot be negative, we discard this solution. Therefore, there were 80 roses ordered and no carnations.