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Can you guys pls help me with this math question

Can you guys pls help me with this math question-example-1
User Giorgiga
by
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1 Answer

6 votes
6 votes

Answer:

Dimensions: 125 m x 250 m

Area: 31,250 m²

Explanation:

Given information:

  • Total amount of fencing = 500m
  • Only 3 sides of the land need to be fenced

First, let us assume that the land is rectangular in shape.

Let
y = length of the side opposite the river

Let
x = length of the other 2 sides of the land

Therefore, we can create two equations from the given information:

Area of land:
A= xy

Perimeter of fence:
2x + y = 500

Rearrange the equation for the perimeter of the fence to make y the subject:


\begin{aligned} \implies 2x + y & = 500\\ y & = 500-2x \end{aligned}

Substitute this into the equation for Area:


\begin{aligned}\implies A & = xy\\& = x(500-2x)\\& = 500x-2x^2 \end{aligned}

To find the value of x that will make the area a maximum, differentiate A with respect to x:


\begin{aligned}A & =500x-2x^2\\\implies (dA)/(dx)& =500-4x\end{aligned}

Set it to zero and solve for x:


\begin{aligned}(dA)/(dx) & =0\\ \implies 500-4x & =0 \\ x & = 125 \end{aligned}

Substitute the found value of x into the original equation for the perimeter and solve for y:


\begin{aligned}2x + y & = 500\\\implies 2(125)+y & = 500\\250+y & = 500\\y & = 250\end{aligned}

Therefore, the dimensions that will give Christine the maximum area are:

125 m x 250 m (where 250 m is the side opposite the river)

The maximum area is:


\begin{aligned}\implies \sf Area_(max) & = xy\\& = 125 \cdot 250\\& = 31250\: \sf m^2 \end{aligned}

User Joe White
by
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