Answer:
✅Figure E has more area
✅Figure E has 5.14 units² much more than Figure D.
Explanation:
The logic to solving this kind of problem is to decompose and each of the figure to find out how many squares and circles are there in each figure, them calculate the area of each figure using the formula for area of square and area of a circle.
✍️Figure D:
Figure D is composed of 2 squares and 4 semicircles (2 full circles).
Since side length of 1 square = 1 unit, therefore, radius of the semi-circle/circle = 1 unit.
Area of the 2 squares = 2(s²) = 2(1²) = 2 unit²
Area of the 2 full circles = 2(πr²) = 2(3.14*1²) = 6.28 unit²
Area of Figure D = 2 + 6.28 = 8.28 unit²
✍️Figure E:
Figure E is composed of 4 squares and 6 quarter circles (3 full circles).
Area of the 4 squares = 4(s²) = 4(1²) = 4 unit²
Area of the 3 full circles = 3(πr²) = 3(3.14*1²) = 9.42 units²
Area of figure E = 4 + 9.42 = 13.42 unit²
✅Therefore, we can conclude that Figure E has more area.
✅Figure E has 5.14 unit² more area than Figure D (13.42 - 8.28 = 5.14).