Answer:
a) 2.120
b) 1.796
c) 2.807
d) 1.714
e) 1.356
f) 2.262
Explanation:
The formula used to compute a confidence interval for the mean of a normal population when n is small is the following. x^^\_ +/-\(t text( critical value)\)s/sqrt(n) What is the appropriate t critical value for each of the following confidence levels and sample sizes? (Round your answers to two decimal places.)
(a) 95% confidence, n = 17
We find our degrees of freedom first
= n - 1
= 17 - 1
= 16
The t critical value using the t table =
2.120
(b) 90% confidence, n = 12
We find our degrees of freedom first
= n - 1
= 12 - 1
= 11
The t critical value using the t table =
1.796
(c) 99% confidence, n = 24
We find our degrees of freedom first
= n - 1
= 24 - 1
= 23
The t critical value using the t table = 2.807
(d) 90% confidence, n = 24
We find our degrees of freedom first
= n - 1
= 24 - 1
= 23
The t critical value using the t table =
1.714
(e) 80% confidence, n = 13
We find our degrees of freedom first
= n - 1
= 13- 1
= 12
The t critical value using the t table = 1.356
(f) 95% confidence, n = 10
We find our degrees of freedom first
= n - 1
= 10 - 1
= 9
The t critical value using the t table =
2.262