Question

A potential difference of 107 mV exists between the inner and outer surfaces of a cell membrane. The inner surface is negative relative to the outer surface. How much work is required to eject a positive sodium ion (Na ) from the interior of the cell?

Answer 1

The workdone is
`W = 1.712 *10^(-20 ) \ J`

Step-by-step explanation:

From the question we are told that

The potential difference is
`V = 107 mV = 107 *10^(-3) \ V`

Generally the charge on
`Na^(+)` is
`Q_(Na^(+)) = 1.60 *10^(-19 ) \ C`

Generally the workdone is mathematically represented as

`W = Q_(Na^(+))V`

=>
`W = 1.60 *10^(-19 ) * 107 *10^(-3)`

=>
`W = 1.712 *10^(-20 ) \ J`