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This is how many classes students at Bronx College take this semester with the probabilities courses1 2 3 4 5 probability (distribution) of taking that many courses.1.1.6.1.1 The variance for this distribution is approximately.

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Answer:

1

Explanation:

Given the question above :

The probability distribution :

X : ___ 1 ___ 2 ___ 3 ___ 4 ____ 5

P(x): _ 0.1 __ 0.1 __ 0.6 _ 0.1 __ 0.1

The Variance : Var(X) = (Σx²*p(x)) - μ²

μ = E(X) = Σ(X * p(x)) :

Σ(X * p(x)) = (1*0.1)+(2*0.1)+(3*0.6)+(4*0.1)+(5*0.1)

μ = 3

Var(X): [(1^2*0.1)+(2^2*0.1)+(3^2*0.6)+(4^2*0.1)+(5^2*0.1)] - 3²

= 10 - 9

= 1

Hence. Variance = 1

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