Question

A rock dropped down a well takes 2.5 seconds to hit the water. How far below the

top of the well is the surface of the water? [Answer to 1 decimal place)

Answer 1

30.6 m

Step-by-step explanation:

Given:

v₀ = 0 m/s

a = 9.8 m/s²

t = 2.5 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (0 m/s) (2.5 s) + ½ (9.8 m/s²) (2.5 s)²

Δy = 30.6 m