This question is incomplete, the complete question is;
Starting with the full Bernoulli’s equation, simplify the equation for the case diagrammed below, where Point 1 is at the top of the water at height h1, with negligible flow speed v1=0, and Point 2 is at height h2=0. Both Point 1 and Point 2 are open to the atmosphere so P1 = P2 = Patm.
According to your equation, what is the functional relationship between the height of the water h1 and the speed of the flow v2 at Point 2?
Answer:
the functional relationship between the height of the water h1 and the speed of the flow v2 at Point 2 is v2 = √2gh1
Step-by-step explanation:
Gravitational acceleration = g
Density of water = P
Pressure of the water at point 1 = p1 = patm
Speed of the water at point 1 = v1 = 0 m/s
Height of point 1 = h1
Pressure of the water at point 2 = p2 = patm
Speed of the water at point 2 = v2
Height of point 2 = h2 = 0 m
Now, Using Bernoulli's equation at point 1 and 2,
p1 + Pv1²/2 + Pgh1 = p2 + Pv2²/2 + Pgh2
patm + P(0)²/2 + Pgh1 = patm + Pv2²/2 + Pg(0)
Pgh1 = Pv2²/2
gh1 = v2²/2
v2² = 2gh1
v2 = √2gh1
Therefore the functional relationship between the height of the water h1 and the speed of the flow v2 at Point 2 is v2 = √2gh1