Question

A 3kg flower pot s at rest over a horizontal surface if the fsmax required to move it is 6.77 N WHAT WILL BE THE COEFFICIENT OF FRICTION FIR THE FLOWER POT

Answer 1

`\mu=0.23`

Step-by-step explanation:

Given that,

Mass of a flower pot = 3 kg

The force that is required to move the pot is 6.77 N

We need to find the coefficient of friction for the flower pot.

The force required to move an object in terms of coefficient of friction is given by :

`F=\mu N`

N is normal force

`F=\mu mg\\\\\mu=(F)/(mg)\\\\\mu=(6.77)/(3* 9.8)\\\\\mu=0.23`

So, the coefficient of friction for the flower pot is 0.23.