Question

I need help with this problem.

please help

Directions: Solve each system by substitution.​

Answer 1

x=-1

y=-6

Explanation:

To solve for x and y in 2x+3y=-20 start by substituting y for 6x

2x+3(6x)=-20 simplify the left side by multiplying 3 and 6x then add the product to 2x

20x=-20 now divide 20 on both sides

x=-1

now that you know what x is, you can solve for y

2x+3y=-20 substitute x for -1

2(-1)+3y=-20 now simplify by multiplying 2 and -1

-2+3y=-20 add -2 on both sides

3y=-18 now divide 3 on both sides

y=-6

Answer 2

(-1,-6)

Explanation:

Plug 6x for y into the bottom equation:

2x+3(6x)= -20

2x+18x= -20

20= -20

x= -1

Substitute -1 for x in the equation for y:

y=6(-1)

y=-6

I hope I could help :)