Question

Find the probability that a randomly

selected point within the circle falls
in the red shaded area.
r = 4 cm
[?]%
Round to the nearest tenth of a percent.
Enter

Answer 1

`31.8\%`

Explanation:

The area of the circle is
`A=\pi r^2=\pi(4)^2=16\pi`

The area of the triangle is
`A=(bh)/(2)=(8*4)/(2)=(32)/(2)=16`

Hence, the probability of a randomly selected point within the circle falls in the red shaded area is
`(16)/(16\pi)=(1)/(\pi)\approx0.318\approx31.8\%`