Question

Calculate the following quantity: molarity of a solution prepared by diluting 45.45 mL of 0.0404 M ammonium sulfate to 550.00 mL. M solution

Answer 1

`M_2=3.34x10^(-3)M`

Step-by-step explanation:

Hello!

In this case, since a dilution process implies that the moles of the solute remain the same before and after the addition of diluting water, we can write:

`M_1V_1=M_2V_2`

Thus, since we know the volume and concentration of the initial sample, we compute the resulting concentration as shown below:

`M_2=(M_2V_2)/(V_1) =(45.45mL*0.0404M)/(550.00mL)\\\\M_2=3.34x10^(-3)M`

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